Optimal. Leaf size=142 \[ \frac{23 a^4 \cot ^3(c+d x)}{15 d}+\frac{4 i a^4 \cot ^2(c+d x)}{d}-\frac{8 a^4 \cot (c+d x)}{d}+\frac{8 i a^4 \log (\sin (c+d x))}{d}-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{3 i \cot ^4(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{5 d}-8 a^4 x \]
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Rubi [A] time = 0.291448, antiderivative size = 142, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {3553, 3593, 3591, 3529, 3531, 3475} \[ \frac{23 a^4 \cot ^3(c+d x)}{15 d}+\frac{4 i a^4 \cot ^2(c+d x)}{d}-\frac{8 a^4 \cot (c+d x)}{d}+\frac{8 i a^4 \log (\sin (c+d x))}{d}-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{3 i \cot ^4(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{5 d}-8 a^4 x \]
Antiderivative was successfully verified.
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Rule 3553
Rule 3593
Rule 3591
Rule 3529
Rule 3531
Rule 3475
Rubi steps
\begin{align*} \int \cot ^6(c+d x) (a+i a \tan (c+d x))^4 \, dx &=-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{1}{5} \int \cot ^5(c+d x) (a+i a \tan (c+d x))^2 \left (-12 i a^2+8 a^2 \tan (c+d x)\right ) \, dx\\ &=-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{3 i \cot ^4(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{5 d}-\frac{1}{20} \int \cot ^4(c+d x) (a+i a \tan (c+d x)) \left (92 a^3+68 i a^3 \tan (c+d x)\right ) \, dx\\ &=\frac{23 a^4 \cot ^3(c+d x)}{15 d}-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{3 i \cot ^4(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{5 d}-\frac{1}{20} \int \cot ^3(c+d x) \left (160 i a^4-160 a^4 \tan (c+d x)\right ) \, dx\\ &=\frac{4 i a^4 \cot ^2(c+d x)}{d}+\frac{23 a^4 \cot ^3(c+d x)}{15 d}-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{3 i \cot ^4(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{5 d}-\frac{1}{20} \int \cot ^2(c+d x) \left (-160 a^4-160 i a^4 \tan (c+d x)\right ) \, dx\\ &=-\frac{8 a^4 \cot (c+d x)}{d}+\frac{4 i a^4 \cot ^2(c+d x)}{d}+\frac{23 a^4 \cot ^3(c+d x)}{15 d}-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{3 i \cot ^4(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{5 d}-\frac{1}{20} \int \cot (c+d x) \left (-160 i a^4+160 a^4 \tan (c+d x)\right ) \, dx\\ &=-8 a^4 x-\frac{8 a^4 \cot (c+d x)}{d}+\frac{4 i a^4 \cot ^2(c+d x)}{d}+\frac{23 a^4 \cot ^3(c+d x)}{15 d}-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{3 i \cot ^4(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{5 d}+\left (8 i a^4\right ) \int \cot (c+d x) \, dx\\ &=-8 a^4 x-\frac{8 a^4 \cot (c+d x)}{d}+\frac{4 i a^4 \cot ^2(c+d x)}{d}+\frac{23 a^4 \cot ^3(c+d x)}{15 d}+\frac{8 i a^4 \log (\sin (c+d x))}{d}-\frac{\cot ^5(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{5 d}-\frac{3 i \cot ^4(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{5 d}\\ \end{align*}
Mathematica [B] time = 3.46985, size = 359, normalized size = 2.53 \[ \frac{a^4 \csc (c) \csc ^5(c+d x) (\cos (4 d x)+i \sin (4 d x)) \left (345 \sin (2 c+d x)-275 \sin (2 c+3 d x)-120 \sin (4 c+3 d x)+79 \sin (4 c+5 d x)+600 d x \cos (2 c+d x)-210 i \cos (2 c+d x)+300 d x \cos (2 c+3 d x)-90 i \cos (2 c+3 d x)-300 d x \cos (4 c+3 d x)+90 i \cos (4 c+3 d x)-60 d x \cos (4 c+5 d x)+60 d x \cos (6 c+5 d x)+960 \sin (c) \sin ^5(c+d x) \tan ^{-1}(\tan (5 c+d x))-30 \cos (d x) \left (-5 i \log \left (\sin ^2(c+d x)\right )+20 d x-7 i\right )-150 i \cos (2 c+d x) \log \left (\sin ^2(c+d x)\right )-75 i \cos (2 c+3 d x) \log \left (\sin ^2(c+d x)\right )+75 i \cos (4 c+3 d x) \log \left (\sin ^2(c+d x)\right )+15 i \cos (4 c+5 d x) \log \left (\sin ^2(c+d x)\right )-15 i \cos (6 c+5 d x) \log \left (\sin ^2(c+d x)\right )+445 \sin (d x)\right )}{120 d (\cos (d x)+i \sin (d x))^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.056, size = 113, normalized size = 0.8 \begin{align*} -8\,{a}^{4}x-8\,{\frac{{a}^{4}\cot \left ( dx+c \right ) }{d}}-8\,{\frac{{a}^{4}c}{d}}+{\frac{4\,i{a}^{4} \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{d}}-{\frac{i{a}^{4} \left ( \cot \left ( dx+c \right ) \right ) ^{4}}{d}}+{\frac{7\,{a}^{4} \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{3\,d}}+{\frac{8\,i{a}^{4}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-{\frac{{a}^{4} \left ( \cot \left ( dx+c \right ) \right ) ^{5}}{5\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.57646, size = 147, normalized size = 1.04 \begin{align*} -\frac{120 \,{\left (d x + c\right )} a^{4} + 60 i \, a^{4} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) - 120 i \, a^{4} \log \left (\tan \left (d x + c\right )\right ) + \frac{120 \, a^{4} \tan \left (d x + c\right )^{4} - 60 i \, a^{4} \tan \left (d x + c\right )^{3} - 35 \, a^{4} \tan \left (d x + c\right )^{2} + 15 i \, a^{4} \tan \left (d x + c\right ) + 3 \, a^{4}}{\tan \left (d x + c\right )^{5}}}{15 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.31537, size = 666, normalized size = 4.69 \begin{align*} \frac{-840 i \, a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 2220 i \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} - 2620 i \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 1460 i \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} - 316 i \, a^{4} +{\left (120 i \, a^{4} e^{\left (10 i \, d x + 10 i \, c\right )} - 600 i \, a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 1200 i \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} - 1200 i \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 600 i \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} - 120 i \, a^{4}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} - 1\right )}{15 \,{\left (d e^{\left (10 i \, d x + 10 i \, c\right )} - 5 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 10 \, d e^{\left (6 i \, d x + 6 i \, c\right )} - 10 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 5 \, d e^{\left (2 i \, d x + 2 i \, c\right )} - d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 5.93892, size = 226, normalized size = 1.59 \begin{align*} \frac{8 i a^{4} \log{\left (e^{2 i d x} - e^{- 2 i c} \right )}}{d} + \frac{- \frac{56 i a^{4} e^{- 2 i c} e^{8 i d x}}{d} + \frac{148 i a^{4} e^{- 4 i c} e^{6 i d x}}{d} - \frac{524 i a^{4} e^{- 6 i c} e^{4 i d x}}{3 d} + \frac{292 i a^{4} e^{- 8 i c} e^{2 i d x}}{3 d} - \frac{316 i a^{4} e^{- 10 i c}}{15 d}}{e^{10 i d x} - 5 e^{- 2 i c} e^{8 i d x} + 10 e^{- 4 i c} e^{6 i d x} - 10 e^{- 6 i c} e^{4 i d x} + 5 e^{- 8 i c} e^{2 i d x} - e^{- 10 i c}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.53522, size = 288, normalized size = 2.03 \begin{align*} \frac{3 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 30 i \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 155 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 600 i \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 7680 i \, a^{4} \log \left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + i\right ) + 3840 i \, a^{4} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) + 2370 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + \frac{-8768 i \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 2370 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 600 i \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 155 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 30 i \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 3 \, a^{4}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5}}}{480 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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